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30 changes: 30 additions & 0 deletions problem1Solution.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
//Time Complexity : O(log n)
//Space Complexity : O(1)
//Search in a Rotated Sorted Array

public class problem1Solution {
public int search(int[] nums, int target) {
int left = 0;
int right = nums.length-1;
while(left<=right){
int mid = left + (right - left)/2;
if(nums[mid]== target) return mid;
if(nums[left]<=nums[mid]) {
if (target > nums[mid] || target < nums[left] )
left = mid + 1;
else {
right = mid -1;
}
}
else {
if( target < nums[mid] || target > nums[right]){
right = mid - 1;
}
else {
left = mid + 1;
}
}
}
return -1;
}
}
25 changes: 25 additions & 0 deletions problem2Solution.java
Original file line number Diff line number Diff line change
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//Time complexity : O(log n)
//Space complexity : O(1)
//Search Inside a Sorted Array whose Length is unknown

public class problem2Solution {
public int search(ArrayReader reader, int target) {
int left = 0;
int right = 1;
while(reader.get(right) <= target) {
left = right;
right = 2*right;
}

while(left <= right) {
int mid = left + (right - left)/2;
if(reader.get(mid) == target) return mid;
if(reader.get(mid) < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}
return -1;
}
}
28 changes: 28 additions & 0 deletions problem3Solution.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,28 @@
//Time Complexity : O(log m*n)
//Space Complexity : O(1)
//Search a 2D Matrix
public class problem3Solution {
public boolean searchMatrix(int[][] matrix, int target) {
int r = matrix.length;
int c = matrix[0].length;

int left = 0;
int right = (r*c)-1;

while (left <= right) {
int mid = left + (right - left)/2;
int midRow = mid/c;
int midCol = mid%c;
if(matrix[midRow][midCol]== target) {
return true;
}
else if(matrix[midRow][midCol]< target) {
left = mid+1;
}
else {
right = mid-1;
}
}
return false;
}
}