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Updated solution: Variant of binary search in C++, 14[ms] ; O(lg(m+n))
Easy to understand with explanation.
Description
Suppose the two arrays are A and B.
Perform the following variant of binary search first in A then B to find the median.
Start from low = 0, high = |A|, guess i = floor (low + high)/2
For the median m, there should be total half = floor (|A| + |B| + 1) / 2 elements not greater than it.
Since there are i + 1 elements not greater than A[i] in A,
There should be half - (i + 1) elements not greater than A[i] in B.
Denote j = half - i - 2, thus we can compare if B[j] <= A[i] <= B[j + 1] is satisfied. This indicates
That the guess is the correct median.
Otherwise, we can easily tell if the guess is too small or too big, then halve the elements to adjust
the guess.
Fixes #134
Type of change
Checklist:
README.md