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joseantoniochacon · Jun 5, 2024 · 13005a2 · 13005a2
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diff --git a/...subjects-taught-by-each-teacher/2356-number-of-unique-subjects-taught-by-each-teacher.sql b/...subjects-taught-by-each-teacher/2356-number-of-unique-subjects-taught-by-each-teacher.sql
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+# Write your MySQL query statement below
+SELECT teacher_id, COUNT(DISTINCT subject_id) AS cnt FROM Teacher GROUP BY teacher_id;