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⚡ Bolt: [performance improvement] optimize material_extractor loops #86

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⚡ Bolt: [performance improvement] optimize material_extractor loops #86

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3 changes: 3 additions & 0 deletions .jules/bolt.md
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## 2025-05-20 - Pre-compiling Regex in Loops
**Learning:** `re.findall(pattern, string)` recompiles (or retrieves from cache) the pattern on every call. In high-frequency functions called inside loops (like complexity estimation), this overhead adds up.
**Action:** Always pre-compile regexes (`re.compile`) into module-level or class-level constants if they are used repeatedly, especially in tight loops or recursive functions.
## 2026-04-25 - O(N*M) to O(N) lookup refactoring
**Learning:** When replacing nested loops with dictionary lookups for performance in finding matching elements (e.g., matching solutions to exercises), building an O(N) lookup dictionary first is very effective.
**Action:** Use dictionary comprehensions or manual population (like `solutions_by_label = {sol['exercise_label']: sol for sol in material['solutions']}`) to eliminate inner loops when mapping keys to values.
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Copilot AI Apr 25, 2026

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This guidance suggests using a dict comprehension for the lookup table, but dict comprehensions are "last value wins" for duplicate keys. In cases where multiple solutions share the same exercise_label, that would change semantics compared to the original nested-loop+break (first match wins). Consider updating the note to recommend manual population / setdefault when first-match behavior must be preserved, and only suggest a comprehension when duplicates are impossible or last-match is desired.

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**Action:** Use dictionary comprehensions or manual population (like `solutions_by_label = {sol['exercise_label']: sol for sol in material['solutions']}`) to eliminate inner loops when mapping keys to values.
**Action:** Preserve the original duplicate-key semantics when building the lookup: if the nested-loop version used `break` on the first match, populate manually with `setdefault` (for example, `solutions_by_label = {}; for sol in material['solutions']: solutions_by_label.setdefault(sol['exercise_label'], sol)`) so the first match wins. Only use a dict comprehension like `solutions_by_label = {sol['exercise_label']: sol for sol in material['solutions']}` when duplicate labels are impossible or when last-match-wins behavior is desired.

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