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Added 1.19
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milesdai committed Jun 7, 2018
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\end{circuit}

Now we have a simple RC circuit which we can apply Equation 1.21 to. The voltage across the capacitor is given by
\[V(t) = V_\text{final}(1 - e^{-t/RC}) = V_\Th (1 - e^{-t/R_\Th C} = \mans{\frac{1}{2}V_\in (1 - e^{-t\times 10^{-3}})}\]
\[V(t) = V_\text{final}(1 - e^{-t/RC}) = V_\Th (1 - e^{-t/R_\Th C} = \mans{\frac{1}{2}V_\in (1 - e^{-t/5 \times 10^{-4}})}\]

\todo{Add graph}

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This gives us
\[\mans{t = 0.01\text{s}}\]

\ex{1.19}
The magnetic flux produced within the coil is proportional to the number of turns. Now, because the inductance of the inductor is proportional to the amount of magnetic flux that passes through all the coils, it is proportional to the product of the magnetic flux and the number of coils. Thus the inductance is propotional to the square of the number of turns.
\todo{Check/clarify this answer}

\end{document}

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