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Understand what the interviewer is asking for by using test cases and questions about the problem.
What if n is larger than the length of the string?
This won't be the case, since 0 < n < len(s).
P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Slice the input string into two components and then combine them at the end.
1) Slice the string from the beginning up to the index n
2) Slice the string from the index after n to the end
3) Return these two components added together in the order: first, last
I-mplement
defremove_char(s, n):
# Create a new string 'first_part' that includes all characters from the beginning of 's' up to the character at index 'n' (not inclusive).first_part=s[:n]
# Create a new string 'last_part' that includes all characters from the character at index 'n+1' to the end of 's'.last_part=s[n+1:]
# Return the result by concatenating 'first_part' and 'last_part', effectively removing the character at index 'n'.returnfirst_part+last_part