Added a new algorithm

Python/Check whether a no is a power of two or not.py

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+'''Write a program to find whether a given number is a power of 2 or not.
+
+Output Format:
+Print 'YES' or 'NO' accordingly
+
+Example:
+
+Input:
+64
+
+Output:
+YES
+
+Input:
+48
+
+Output:
+NO
+
+Explanation:
+In the first example, 64 is a power of 2 so the answer is YES.
+The second number is not a power of 2 hence the answer is NO.'''
+
+#The Code
+
+import math #math module for mathematical functions
+n=int(input("Enter the number"))
+def log2(n): #find log2 of the given number 
+  l=math.log10(n)/math.log10(2)
+  return(l)
+def isPower(n): #checking if a number is power of two
+    return (math.ceil(log2(n)) == math.floor(log2(n))) #comparisson of floor and ceil values
+if(isPower(n)): #printing output
+    print("YES", end="")
+else: 
+    print("NO", end="")