java_program

Java/rotate_delete.java

@@ -0,0 +1,57 @@
+
+// Given an array arr integers. Assume sz to be the initial size of the array. Do the following operations exactly sz/2 times. In every kth (1<= k <= sz/2) operation:
+
+// Right-rotate the array clockwise by 1.
+// Delete the (n– k + 1)th element from begin.
+// Now, Return the first element of the array.
+
+
+import java.io.*;
+import java.lang.*;
+import java.util.*;
+
+
+class Abhishek {
+    public static void main(String[] args) throws IOException {
+        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
+        int t = Integer.parseInt(br.readLine());
+        while (t-- > 0) {
+            String line = br.readLine();
+            String[] tokens = line.split(" ");
+
+            // Create an ArrayList to store the integers
+            ArrayList<Integer> arr = new ArrayList<>();
+
+            // Parse the tokens into integers and add to the array
+            for (String token : tokens) {
+                arr.add(Integer.parseInt(token));
+            }
+
+            Solution obj = new Solution();
+            int res = obj.rotateDelete(arr);
+
+            System.out.println(res);
+        }
+    }
+}
+
+
+class Solution {
+    public static int rotateDelete(ArrayList<Integer> arr) {
+        // code here
+        int n = arr.size();
+        if(n == 1 || n == 2)return arr.get(n-1);
+
+        int[] b = {3, 2, 3, 3};
+        int a = 3, j = 0;
+        while(a + 4 <= n){
+            a += 4;
+            j++;
+        }
+
+        for(int i = 0; i < 4; i++){
+            if(a+i == n)return arr.get(b[i]+j-1);
+        }
+        return 0;
+    }
+}