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algorithms/easy/reverse/reverse.js

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// description: https://leetcode-cn.com/problems/reverse-integer/description/
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// 反转整数
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/**
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* @param {number} x
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* @return {number}
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*/
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var reverse = function(x) {
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var ret = 0;
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while (x) {
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ret = ret * 10 + x % 10;
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x = parseInt(x / 10);
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}
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if (ret > Math.pow(2, 31) - 1 || ret < Math.pow(-2, 31)) {
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ret = 0;
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}
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return ret;
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};

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