Running a shell function from .bash.rc, as an argument

[ciqven]

Greetings, this is my first time posting here.

I am trying to auto-start an instance of kitty running yazi from my i3wm config, which will then be slotted into a layout. To launch yazi, I normally use the y shell function yazi provides, which is stored in my ~/.bash.rc. The goal of this function is launching yazi in a way that supports changing cwd when I close it.

However, when I execute kitty y I get the following error:

Failed to launch child: y
With error: No such file or directory

Running kitty yazi does work, so this seems a problem with running shell functions instead of programs. Is there a way to elegantly do this, or do I have to duplicate the function into a shell script so I can run it?

Thanks for considering!

[kovidgoyal]

kitty zsh -ilc "y" replace zsh with your shell obviously.

[ciqven]

Thank you very much for the quick response, this solved it!

kitty bash -il "y" caused the spawned bash to still complain with bash: y: No such file or directory, but adding a c flag to make kitty bash -ilc "y" worked!

Edit: It turns out that kitty bash -ilc "y" ends the bash process and therefore closes the opened kitty instance after y completes. However launching another bash on completion with kitty bash -ilc 'y;exec bash' does work, and also propagates the cwd set by yazi's y