refactor: Remove interval arg to cpu_percent

* By removing `interval`, the function returns immediately without blocking

Signed-off-by: Mahendra Paipuri <[email protected]>

Author: mahendrapaipuri

jupyter_resource_usage/api.py

@@ -95,7 +95,7 @@ async def get(self):
     def _get_cpu_percent(self, all_processes):
         def get_cpu_percent(p):
             try:
-                return p.cpu_percent(interval=0.05)
+                return p.cpu_percent()
             # Avoid littering logs with stack traces complaining
             # about dead processes having no CPU usage
             except: