diff --git a/1050-actors-and-directors-who-cooperated-at-least-three-times/README.md b/1050-actors-and-directors-who-cooperated-at-least-three-times/README.md new file mode 100644 index 0000000..635bbb1 --- /dev/null +++ b/1050-actors-and-directors-who-cooperated-at-least-three-times/README.md @@ -0,0 +1,45 @@ +

1050. Actors and Directors Who Cooperated At Least Three Times

Easy


SQL Schema

Table: ActorDirector

+ +
+-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| actor_id    | int     |
+| director_id | int     |
+| timestamp   | int     |
++-------------+---------+
+timestamp is the primary key (column with unique values) for this table.
+
+ +

 

+ +

Write a solution to find all the pairs (actor_id, director_id) where the actor has cooperated with the director at least three times.

+ +

Return the result table in any order.

+ +

The result format is in the following example.

+ +

 

+

Example 1:

+ +
Input: 
+ActorDirector table:
++-------------+-------------+-------------+
+| actor_id    | director_id | timestamp   |
++-------------+-------------+-------------+
+| 1           | 1           | 0           |
+| 1           | 1           | 1           |
+| 1           | 1           | 2           |
+| 1           | 2           | 3           |
+| 1           | 2           | 4           |
+| 2           | 1           | 5           |
+| 2           | 1           | 6           |
++-------------+-------------+-------------+
+Output: 
++-------------+-------------+
+| actor_id    | director_id |
++-------------+-------------+
+| 1           | 1           |
++-------------+-------------+
+Explanation: The only pair is (1, 1) where they cooperated exactly 3 times.
+
+
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