Table: Person
+-------------+---------+ +| Column Name | Type | ++-------------+---------+ +| personId | int | +| lastName | varchar | +| firstName | varchar | ++-------------+---------+ +personId is the primary key (column with unique values) for this table. +This table contains information about the ID of some persons and their first and last names. ++ +
+ +
Table: Address
+-------------+---------+ +| Column Name | Type | ++-------------+---------+ +| addressId | int | +| personId | int | +| city | varchar | +| state | varchar | ++-------------+---------+ +addressId is the primary key (column with unique values) for this table. +Each row of this table contains information about the city and state of one person with ID = PersonId. ++ +
+ +
Write a solution to report the first name, last name, city, and state of each person in the Person table. If the address of a personId is not present in the Address table, report null instead.
Return the result table in any order.
+ +The result format is in the following example.
+ ++
Example 1:
+ +Input: +Person table: ++----------+----------+-----------+ +| personId | lastName | firstName | ++----------+----------+-----------+ +| 1 | Wang | Allen | +| 2 | Alice | Bob | ++----------+----------+-----------+ +Address table: ++-----------+----------+---------------+------------+ +| addressId | personId | city | state | ++-----------+----------+---------------+------------+ +| 1 | 2 | New York City | New York | +| 2 | 3 | Leetcode | California | ++-----------+----------+---------------+------------+ +Output: ++-----------+----------+---------------+----------+ +| firstName | lastName | city | state | ++-----------+----------+---------------+----------+ +| Allen | Wang | Null | Null | +| Bob | Alice | New York City | New York | ++-----------+----------+---------------+----------+ +Explanation: +There is no address in the address table for the personId = 1 so we return null in their city and state. +addressId = 1 contains information about the address of personId = 2. ++