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Self-Join.sql
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72 lines (52 loc) · 1.81 KB
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-- #1
SELECT count(name) FROM stops;
-- #2
SELECT id FROM stops WHERE name = 'Craiglockhart';
-- #3
SELECT id, name FROM stops JOIN route ON route.stop = stops.id WHERE route.num = '4' AND route.company = 'LRT';
-- #4
SELECT company, num, COUNT(*)
FROM route WHERE stop=149 OR stop=53
GROUP BY company, num
HAVING COUNT(*) = 2;
-- #5
SELECT a.company, a.num, a.stop, b.stop
FROM route a JOIN route b ON
(a.company=b.company AND a.num=b.num)
WHERE a.stop=53 AND b.stop = 149;
-- #6
SELECT a.company, a.num, stopa.name, stopb.name
FROM route a JOIN route b ON
(a.company=b.company AND a.num=b.num)
JOIN stops stopa ON (a.stop=stopa.id)
JOIN stops stopb ON (b.stop=stopb.id)
WHERE stopa.name='Craiglockhart' AND stopb.name='London Road';
-- #7
-- Use DISTINCT only once
SELECT DISTINCT a.company, a.num
FROM route a JOIN route b ON
(a.company=b.company AND a.num=b.num)
WHERE a.stop=115 AND b.stop = 137;
-- #8
SELECT DISTINCT a.company, a.num
FROM route a JOIN route b ON
(a.company=b.company AND a.num=b.num)
JOIN stops stopa ON (a.stop=stopa.id)
JOIN stops stopb ON (b.stop=stopb.id)
WHERE stopa.name='Craiglockhart' AND stopb.name='Tollcross';
-- #9
SELECT DISTINCT stopb.name, a.company, a.num
FROM route a JOIN route b ON
(a.company=b.company AND a.num=b.num)
JOIN stops stopa ON (a.stop=stopa.id)
JOIN stops stopb ON (b.stop=stopb.id)
WHERE a.company = 'LRT' AND stopa.name='Craiglockhart';
-- #10
SELECT a.num, a.company, stops.name, d.num, d.company
FROM route a JOIN route b ON a.company = b.company AND a.num = b.num
JOIN stops ON b.stop = stops.id
JOIN route c ON c.stop = stops.id
JOIN route d ON c.company = d.company AND c.num = d.num
WHERE a.stop = (SELECT id FROM stops WHERE name = 'Craiglockhart')
AND d.stop = (SELECT id FROM stops WHERE name = 'Lochend')
ORDER BY a.num, stops.name, d.num;