113.md

Results of GPT-3.5 on HumanEval/113

Date: 18 July, 2023
Model: gpt-3.5-turbo
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

Tokens: 199

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"

Runs

❌ Run 1

Start time: 2023-07-18 17:09:48
Duration: 3.07s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 2

Start time: 2023-07-18 17:09:45
Duration: 3.1s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 3

Start time: 2023-07-18 17:09:41
Duration: 3.32s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 4

Start time: 2023-07-18 17:09:38
Duration: 3.15s
Completion tokens: 68
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for char in string:
            if int(char) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 5

Start time: 2023-07-18 17:09:35
Duration: 2.96s
Completion tokens: 68
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for char in string:
            if int(char) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 6

Start time: 2023-07-18 17:09:32
Duration: 2.92s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 7

Start time: 2023-07-18 17:09:30
Duration: 2.54s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 8

Start time: 2023-07-18 17:09:26
Duration: 3.06s
Completion tokens: 69
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for digit in string:
            if int(digit) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 9

Start time: 2023-07-18 17:09:23
Duration: 2.64s
Completion tokens: 68
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for char in string:
            if int(char) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result

❌ Run 10

Start time: 2023-07-18 17:09:20
Duration: 3.39s
Completion tokens: 68
Result: Fail

def odd_count(lst):
    result = []
    for string in lst:
        count = 0
        for char in string:
            if int(char) % 2 != 0:
                count += 1
        result.append("the number of odd elements in the string {} of the input.".format(count))
    return result