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Results of Code LLama 34B on HumanEval/73

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """ans = 0
    for i in range(len(arr) // 2):
        if arr[i] != arr[len(arr) - i - 1]:
            ans += 1
    return ans

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1

Runs

❌ Run 1

Start time: 2023-09-01 02:47:29
Duration: 27.08s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]) + 1

    return dp[n][n]

❌ Run 2

Start time: 2023-09-01 02:50:28
Duration: 12.81s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    if n == 0:
        return 0
    left = 0
    right = n - 1
    while left < right:
        if arr[left] != arr[right]:
            arr[left], arr[right] = arr[right], arr[left]
            left += 1
            right -= 1
        else:
            left += 1
            right -= 1
    return n - left

❌ Run 3

Start time: 2023-09-01 02:53:26
Duration: 20.87s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]) + 1

    return dp[n][n]

❌ Run 4

Start time: 2023-09-01 02:56:21
Duration: 24.02s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j] + 1)

    return dp[n][n]

❌ Run 5

Start time: 2023-09-01 02:59:17
Duration: 23.4s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j] + 1, dp[i][j - 1] + 1)

    return dp[n][n]

❌ Run 6

Start time: 2023-09-01 03:02:20
Duration: 21.36s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]) + 1

    return dp[n][n]

❌ Run 7

Start time: 2023-09-01 03:05:25
Duration: 20.35s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j] + 1)

    return dp[n][n]

❌ Run 8

Start time: 2023-09-01 03:08:26
Duration: 12.09s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    if n == 0:
        return 0
    left = 0
    right = n - 1
    while left < right:
        if arr[left] != arr[right]:
            arr[left], arr[right] = arr[right], arr[left]
            left += 1
            right -= 1
        else:
            left += 1
            right -= 1
    return n - left

❌ Run 9

Start time: 2023-09-01 03:11:22
Duration: 29.12s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j] + 1)

    return dp[n][n]

❌ Run 10

Start time: 2023-09-01 03:14:24
Duration: 24.11s
Result: Fail

def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    n = len(arr)
    dp = [[0] * (n + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        for j in range(1, n + 1):
            if arr[i - 1] == arr[n - j]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j] + 1, dp[i][j - 1] + 1)

    return dp[n][n]