Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 5
Total runs: 10
Success rate: 50%
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
def check(candidate):
# Check some simple cases
assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)"
assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)"
assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3 (good for debugging!)"
assert candidate([-10, -20, -30]) == 0 , "This prints if this assert fails 4 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([-1, -2, 8]) == 0, "This prints if this assert fails 5 (also good for debugging!)"
assert candidate([0.2, 3, 5]) == 34, "This prints if this assert fails 6 (also good for debugging!)"
lst = list(range(-99, 100, 2))
odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])
assert candidate(lst) == odd_sum , "This prints if this assert fails 7 (good for debugging!)"
Start time: 2023-09-01 02:46:06
Duration: 9.27s
Result: Fail
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 == 1 and num > 0 and num.is_integer():
result += num ** 2
return result
Start time: 2023-09-01 02:49:01
Duration: 9.11s
Result: Pass
def double_the_difference(lst):
"""
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
"""
result = 0
for num in lst:
if num % 2 == 1 and num > 0:
result += num ** 2
return result
Start time: 2023-09-01 02:51:59
Duration: 9.38s
Result: Fail
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 != 0 and num > 0 and num.is_integer():
result += num ** 2
return result
Start time: 2023-09-01 02:54:52
Duration: 4.06s
Result: Fail
def double_the_difference(lst):
result = 0
for num in lst:
if num % 2 == 1 and num > 0 and num.is_integer():
result += num ** 2
return result
Start time: 2023-09-01 02:57:52
Duration: 8.89s
Result: Fail
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 != 0 and num > 0 and num.is_integer():
result += num ** 2
return result
Start time: 2023-09-01 03:00:54
Duration: 9.31s
Result: Fail
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 == 1 and num > 0 and num.is_integer():
result += num ** 2
return result
Start time: 2023-09-01 03:03:55
Duration: 8.68s
Result: Pass
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 == 1 and num > 0:
result += num ** 2
return result
Start time: 2023-09-01 03:06:57
Duration: 12.42s
Result: Pass
def double_the_difference(lst):
"""
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
"""
result = 0
for num in lst:
if num % 2 == 1 and num > 0:
result += num ** 2
return result
Start time: 2023-09-01 03:09:59
Duration: 8.85s
Result: Pass
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 == 1 and num > 0:
result += num ** 2
return result
Start time: 2023-09-01 03:12:56
Duration: 8.84s
Result: Pass
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
result = 0
for num in lst:
if num % 2 == 1 and num > 0:
result += num ** 2
return result