diff --git a/labcrossjoin.sql b/labcrossjoin.sql
new file mode 100644
index 0000000..2b5f01d
--- /dev/null
+++ b/labcrossjoin.sql
@@ -0,0 +1,70 @@
+-- Get all pairs of actors that worked together.
+
+select * from sakila.film;
+
+select * from sakila.film_actor;
+
+
+select * 
+from sakila.film_actor a1
+left join sakila.film_actor a2
+on a1.film_id = a2.film_id
+and a1.actor_id <> a2.actor_id;
+
+
+select * from sakila.actor;
+
+-- Get all pairs of customers that have rented the same film more than 3 times.
+
+select * from sakila.rental;
+
+select * from sakila.store;
+
+select * from sakila.customer;
+
+select * from sakila.inventory;
+
+SELECT * FROM SAKILA.FILM;
+
+select * FROM SAKILA.FILM_tEXT;
+
+SELECT * FROM SAKILA.PAYMENT;
+
+SELECT * FROM SAKILA.STAFF;
+
+SELECT C.CUSTOMER_ID AS CUSTOMER1_ID, SUB1.CUSTOMER_ID AS CUSTOMER_ID_2, F.FILM_ID, COUNT(F.FILM_ID) AS N_RENTED_FILMS
+FROM SAKILA.CUSTOMER C
+LEFT JOIN SAKILA.RENTAL R ON R.CUSTOMER_ID = C.CUSTOMER_ID
+LEFT JOIN SAKILA.INVENTORY I ON I.INVENTORY_ID = R.INVENTORY_ID
+LEFT JOIN SAKILA.FILM F ON F.FILM_ID = I.FILM_ID
+LEFT JOIN (
+SELECT C.CUSTOMER_ID, F.FILM_ID
+FROM SAKILA.CUSTOMER C
+LEFT JOIN SAKILA.RENTAL R ON R.CUSTOMER_ID = C.CUSTOMER_ID
+LEFT JOIN SAKILA.INVENTORY I ON I.INVENTORY_ID = R.INVENTORY_ID
+LEFT JOIN SAKILA.FILM F ON F.FILM_ID = I.FILM_ID
+) SUB1
+ON C.CUSTOMER_ID <> SUB1.CUSTOMER_ID AND F.FILM_ID = SUB1.FILM_ID
+GROUP BY 1,2,3
+HAVING N_RENTED_FILMS > 3
+ORDER BY 4 DESC;
+
+-- Get all possible pairs of actors and films.
+
+select * from sakila.actor;
+
+select * from sakila.film;
+
+select * from sakila.film_actor;
+
+select a.actor_id, cj.actor_id, cjf.title, cjf.title
+from sakila.film f
+left join sakila.film_actor fa
+on f.film_id = fa.film_id
+left join sakila.actor a
+on fa.actor_id = a.actor_id
+cross join sakila.actor cj
+cross join sakila.film cjf;
+
+
+