How c trunkate the values by default?

[and-sh]

What is the result of the following expressions
const uint8_t lookupStep = 20 / 100;
const uint8_t lookupStep = 60 / 100;

[mmosca]

they wil both end up as 0.

#include <stdio.h>
#include <stdint.h>

int main(int argc, char **argv)
{
	const uint8_t a = 20 / 100;
        const uint8_t b = 60 / 100;

	const uint8_t roundeda = (20 / 100.0) + 0.5;
	const uint8_t roundedb = (60 / 100.0) + 0.5;


	printf("a: %i b: %i roundeda: %i roundedb: %i\n", a, b, roundeda, roundedb);

	return 0;
}

Output:
a: 0 b: 0 roundeda: 0 roundedb: 1

[and-sh]

Thank you