forked from DengWangBao/Leetcode-Java
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathSymmetricTree.java
118 lines (110 loc) · 3.43 KB
/
SymmetricTree.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
import java.util.LinkedList;
import java.util.Queue;
import java.util.Stack;
public class SymmetricTree {
public boolean isSymmetric(TreeNode root) {
if (root == null) {
return true;
}
return isSymmetric(root.left, root.right);
}
private boolean isSymmetric(TreeNode left, TreeNode right) {
if (left == null && right == null) {
return true;
}
if (left == null || right == null) {
return false;
}
return left.val == right.val && isSymmetric(left.left, right.right) && isSymmetric(left.right, right.left);
}
public boolean isSymmetric2(TreeNode root) {
if (root == null) {
return true;
}
Queue<TreeNode> queue1 = new LinkedList<>();
Queue<TreeNode> queue2 = new LinkedList<>();
queue1.offer(root.left);
queue2.offer(root.right);
while (!queue1.isEmpty() && !queue2.isEmpty()) {
TreeNode left = queue1.poll();
TreeNode right = queue2.poll();
if (left == null && right == null) {
continue;
}
if (left == null || right == null) {
return false;
}
if (left.val != right.val) {
return false;
}
queue1.offer(left.left);
queue1.offer(left.right);
queue2.offer(right.right);
queue2.offer(right.left);
}
return queue1.isEmpty() && queue2.isEmpty();
}
/**
* 基于isSymmetric2,不过只要一个queue就够了
*/
public boolean isSymmetri3(TreeNode root) {
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
queue.offer(root);
while (!queue.isEmpty()) {
TreeNode left = queue.poll();
TreeNode right = queue.poll();
if (left == null && right == null) {
continue;
}
if (left == null || right == null) {
return false;
}
if (left.val != right.val) {
return false;
}
queue.offer(left.left);
queue.offer(right.right);
queue.offer(left.right);
queue.offer(right.left);
}
return true;
}
/**
* 非递归写法
*/
public boolean isSymmetric2(TreeNode left, TreeNode right) {
if (left == null && right == null) {
return true;
}
if (left == null || right == null) {
return false;
}
Stack<TreeNode> stack1 = new Stack<TreeNode>();
Stack<TreeNode> stack2 = new Stack<TreeNode>();
while (!stack1.isEmpty() || left != null) {
if (left != null) {
if (right == null) {
return false;
}
if (left.val != right.val) {
return false;
}
stack1.push(left);
stack2.push(right);
left = left.left;
right = right.right;
} else {
if (right != null) {
return false;
}
if (stack2.isEmpty()) {
return false;
}
left = stack1.pop().right;
right = stack2.pop().left;
}
}
return stack2.isEmpty() && right == null;
}
}