How to register a scalar type with static newScalar()?

[mxmlnglt]

I'd like to register a scalar type the correct way.

Indeed I found this issue #151 which has both a link to the dedicated wiki page and a GraphQLDate example.

However these classes are written the old way i.e. using the super() constructor... which is now @Deprecated.

How can I use the new way by using the static method newScalar()?

Thanks.

[pstarritt-evooq]

Then expose the object as bean

GraphQLScalarType.newScalar()
        .name("LocalDate")
        .description("Description")
        .coercing(new Coercing<Date, String>() {

          @Override
          public String serialize(Object dataFetcherResult) throws CoercingSerializeException {
            // stuff
            return null; 
          }

          @Override
          public Date parseValue(Object input) throws CoercingParseValueException {
               // stuff
            return null;
          }

          @Override
          public Date parseLiteral(Object input) throws CoercingParseLiteralException {
           // stuff
            return null;
          }
        })
        .build();

[mxmlnglt]

Then expose the object as bean

could you be more explicit? thanks.

[pstarritt-evooq]

After you create your new scalar object, you should make it a spring bean which will register it with graphql

[mxmlnglt]

After you create your new scalar object, you should make it a spring bean which will register it with graphql

OK... so no need to call .coercion(..) then?
I'm sorry but I don't really understand.

[oliemansm]

@mxmlnglt
In one of your Spring @Configuration files add something like this (using your own scalar implementation of course):

  @Bean
  public GraphQLScalarType longScalar() {
    return GraphQLScalarType.newScalar()
        .name("Long")
        .description("Long type")
        .coercing(new LongCoercing())
        .build();
  }

This creates and exposes a Spring Bean which is picked up automatically by GraphQL.