NthPower.py

'''
This kata is from check py.checkio.org

You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.

Let's look at a few examples:

array = [1, 2, 3, 4] and N = 2, then the result is 3^2 == 9;
array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.

'''

def NthPower(array,n):
    if (len(array)-1)  >= n:
        for i in range(n+1):
            sqrt = array[i] * array[i]

        if i == n and array[i] == -1:
            return '-1'
        else:
            return sqrt
    else:
        return '-1'

print(NthPower([4,2,24,5,1,2,6,-1],7))