MultiflesOf3or5.py

'''
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.

Note: If the number is a multiple of both 3 and 5, only count it once. Also, if a number is negative, return 0(for languages that do have them)

'''

def solution(number):
    total = 0
    for i in range(number):
        if i %3 == 0:
            total += i
        elif i % 5 == 0:
            total +=i
    return total
           

print(solution(6))