|
| 1 | +""" |
| 2 | +The solution below is really one in which the solution for part 2 has been |
| 3 | +retroactively applied to part 1 as well, simply because it was a fun thing to do. |
| 4 | +
|
| 5 | +Really, part 1 is likely always best solved by a combinatorial/path based solution like |
| 6 | +(bidirectional) BFS or an SAT/SMT solver like Z3, whereas part 2 is very naturally |
| 7 | +expressed as an integer linear program. |
| 8 | +
|
| 9 | +The solution below takes that part 2 solution, and extends it by also formulating |
| 10 | +part 1 as an integer linear program. Here's how that works: In both parts, we want to |
| 11 | +solve a linear equation 𝐴𝑥 = 𝑏 such that 𝑥 is minimal in some sense. In part 1, we |
| 12 | +are solving over 𝔽₂ = {0, 1} and require that 𝑥 has minimal Hamming weight, and in |
| 13 | +part 2, we require that 𝑥 consists of positive integers and has minimal sum. Integer |
| 14 | +programming solvers like the HiGHS-based solver in SciPy that we use below like |
| 15 | +integers better but can be forced to work over the binaries by adding additional |
| 16 | +variables. Concretely, for part 1, instead of solving 𝐴𝑥 = 𝑏 over 𝔽₂, we instead |
| 17 | +allow 𝑥 to be an integer, and introduce new integer variables 𝑡 and solve |
| 18 | +𝐴𝑥 − 2𝑡 = 𝑏, still just minimizing the sum of 𝑥. This works because 2𝑡 vanishes over |
| 19 | +𝔽₂, and because any optimal integer solution will values of 𝑥 in {0, 1}. In other |
| 20 | +words, to solve part 1, we take our part 2 solution and simply add a handful of useful |
| 21 | +auxiliary variables to encode the fact that the matrix equation is now modulo 2. |
| 22 | +
|
| 23 | +While we're at it, note that part 1 is actually the well-known “syndrome decoding” |
| 24 | +problem, also known as “maximum-likelihood decoding”. |
| 25 | +""" |
| 26 | + |
| 27 | +import numpy as np |
| 28 | +from scipy.optimize import linprog |
| 29 | + |
| 30 | + |
| 31 | +with open("input") as f: |
| 32 | + ls = f.read().strip().split("\n") |
| 33 | + |
| 34 | +tasks = [] |
| 35 | +for l in ls: |
| 36 | + toggles, *buttons, counters = l.split() |
| 37 | + toggles = [x == "#" for x in toggles[1:-1]] |
| 38 | + moves = [set(map(int, b[1:-1].split(","))) for b in buttons] |
| 39 | + counters = list(map(int, counters[1:-1].split(","))) |
| 40 | + tasks.append((toggles, moves, counters)) |
| 41 | + |
| 42 | + |
| 43 | +def solve(goal, moves, part1): |
| 44 | + n, m = len(moves), len(goal) |
| 45 | + c = [1] * n |
| 46 | + A_eq = [[i in move for move in moves] for i in range(m)] |
| 47 | + bounds = [(0, None)] * n |
| 48 | + if part1: |
| 49 | + c += [0] * m |
| 50 | + A_eq = np.hstack([A_eq, -2 * np.eye(m)]) |
| 51 | + bounds += [(None, None)] * m |
| 52 | + return linprog(c, A_eq=A_eq, b_eq=goal, bounds=bounds, integrality=True).fun |
| 53 | + |
| 54 | + |
| 55 | +# Part 1 |
| 56 | +print(sum(solve(goal, moves, True) for goal, moves, _ in tasks)) |
| 57 | + |
| 58 | +# Part 2 |
| 59 | +print(sum(solve(goal, moves, False) for _, moves, goal in tasks)) |
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