default value as output with pipe?

[ha1fstack]

https://valibot.dev/playground/?code=JYWwDg9gTgLgBAKjgQwM5wG5wGZQiOAcg2QBtgAjCGQgbgCh6BjCAO1XgGUmALAUxDI4AXkwA6CGBjA2ZABQYxYYGD4KxHKMFYBzOQEoANOJhRk7bNBBywyKKj4BJVjH1GiABkL6GzNhzgoPlQAV1J4UUVUZGw+AAU7BzlufkFjENYAEz5sbT5Mn0YWdghSPjFSCD0g0PDCoA

import * as v from 'valibot';

const Schema = v.optional(v.pipe(v.string(), v.transform(parseInt)), '0');

const result = v.safeParse(Schema, undefined);
console.log(result);

Current 'default value' implementation uses the provided default value as 'input' to the wrapped schema. However I want to provide default value as 'output' of wrapped schema so it skips the pipe and I can provide the desired default output value directly like so:

const Schema = v.optional(v.pipe(v.string(), v.transform(parseInt)), 0); // number 0 instead of string '0'

How should I implement this?

[fabian-hiller]

I would rewrite your schema. See this playground.

import * as v from 'valibot';

const Schema = v.union([
  v.pipe(v.string(), v.transform(parseInt)),
  v.optional(v.number(), 0),
]);

Another option is to use the fallback method instead of the optional schema, but the behavior is different. See this playground.

import * as v from 'valibot';

const Schema = v.fallback(v.pipe(v.string(), v.transform(parseInt)), 0);

[ha1fstack]

Thank you for the detailed answer! The latter implementation suits my case since I only want number input for the field.