Given two strings s and t, check if s is a subsequence of t.
A subsequence of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., "ace" is a subsequence of "abcde" while "aec" is not).
Example 1:
Input: s = "abc", t = "ahbgdc" Output: true
Example 2:
Input: s = "axc", t = "ahbgdc" Output: false
Constraints:
0 <= s.length <= 1000 <= t.length <= 104sandtconsist only of lowercase English letters.
Follow up: If there are lots of incoming
s, say s1, s2, ..., sk where k >= 109, and you want to check one by one to see if t has its subsequence. In this scenario, how would you change your code?
class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
m, n = len(s), len(t)
i = j = 0
while i < m and j < n:
if s[i] == t[j]:
i += 1
j += 1
return i == mclass Solution {
public boolean isSubsequence(String s, String t) {
int m = s.length(), n = t.length();
int i = 0, j = 0;
while (i < m && j < n) {
if (s.charAt(i) == t.charAt(j)) {
++i;
}
++j;
}
return i == m;
}
}class Solution {
public:
bool isSubsequence(string s, string t) {
int m = s.size(), n = t.size();
int i = 0, j = 0;
while (i < m && j < n) {
if (s[i] == t[j]) {
++i;
}
++j;
}
return i == m;
}
};