[Homework 4] 文句處理

[organicguava]

提交連結

https://judge.ccclub.io/status/2b593c4ac73637a70714769ae23640ab

程式碼

keyword = input().split()   #關鍵字串列       
input_lst = []              #文句串列            
while True:
    data = input()
    if data == "end":
        break
    else:
        input_lst.append(data)
inspect=0
#找出每一句裡的關鍵字，並輸出小串列work，裡面包含關鍵字、關鍵字起始index、關鍵字結束index，再把小串列append到index_lst
for i in input_lst:
    index_input_lst = []
    j = 0
    while j <= len(keyword)-1:
        k = 0
        while k <= len(i)-1:
            if i.find(keyword[j],k) == -1:  #使用string.find 尋找關鍵字第一個字的index。若沒有關鍵字結果為-1
                break
            else: 
                m = i.find(keyword[j],k)+len(keyword[j])-1
                work = [keyword[j],i.find(keyword[j],k),m]
                index_input_lst.append(work)
                inspect=1 #若沒有關鍵字，inspect為False
            k = m+1   #從關鍵字的下一個字再開始找
        j+=1
   
    
    if inspect:
        index_input_lst.sort(key = lambda x : (x[1],-x[2]))  #關鍵字index串列，依照開頭文字的index由小到大排、若開頭文字的index一樣，再按照結束文字的index由大到小排
        
        
        need_input_lst = [index_input_lst[0]]        #實際上需要被匡起來的關鍵字index串列              
        p = 1
        while p <= len(index_input_lst)-1:
            if index_input_lst[p][1] > index_input_lst[p-1][2]:
                need_input_lst.append(index_input_lst[p])
            p+=1
     
        j = 0
        sentence = ""   #欲輸出的文句                              
        sentence += i[:need_input_lst[0][1]]  #先加入第一個關鍵字（不含）之前的內容               
        while j<=len(need_input_lst)-2:    #前後都有關鍵字的內容，逐步替換（每次替換會包含前面的關鍵字，不含後面的關鍵字）                  
            part = i[need_input_lst[j][1]:need_input_lst[j+1][1]]
            new_part = part.replace(need_input_lst[j][0],"「" + need_input_lst[j][0] + "」")
            sentence += new_part
            j+=1
        final_part = i[need_input_lst[-1][1]:]     #最後一個關鍵字(含）之後的內容         
        new_final_part = final_part.replace(need_input_lst[-1][0],"「" + need_input_lst[-1][0] + "」") 
        sentence += new_final_part    
    
        print(sentence)
        

if not inspect:
    for i in input_lst:
        print(i)

錯誤訊息

runtime error

問題描述

測資與助教提供的
that a good
that was a very good example
都有正確的output

[SleeperShark]

你只剩一組測資沒有過，應該只是一些小細節上的問題，我把測資給你自己debug試試看，加油~

def print if else elif
def find_keywords(title, keywords):
    ans = str()
    count = 0
    while count < len(title):
        mark = False
        for j in range(len(title), count, -1):
            if title[count:j] in keywords:
                ans += '「' + title[count:j] + '」'
                count = j
                mark = True
        if not mark:
            ans += title[count]
            count += 1
    return ans
keywords = input().split()
s = input()
while s != "end":
    s = find_keywords(s, keywords)
    print(s)
    s = input()
end

[stale]

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