You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
Approach:- either can move each element or can use clever matrix operation(should have learned linear algebra ;) )
So the approach i will explain is of transpose + reversal. Transpose is a method in which row and columns are inter-switched
public void rotate(int[][] matrix) {
int n = matrix[0].length;
for(int i=0;i<matrix.length;i++){
for(int j=i+1;j<matrix[0].length;j++){
int tmp = matrix[j][i];
matrix[j][i] = matrix[i][j];
matrix[i][j] = tmp;
}
}
for(int i=0;i<matrix.length;i++){
for(int j=0;j<(n/2);j++){
int tmp = matrix[i][j];
matrix[i][j] = matrix[i][n-j-1];
matrix[i][n-j-1] = tmp;
}
}
}
Time complexity - O(N) where N is all elements Space complexity - O(1)