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1. Two Sum.py
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44 lines (30 loc) · 1.06 KB
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# Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
# You may assume that each input would have exactly one solution, and you may not use the same element twice.
# You can return the answer in any order.
# Example 1:
# Input: nums = [2,7,11,15], target = 9
# Output: [0,1]
# Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
# Example 2:
# Input: nums = [3,2,4], target = 6
# Output: [1,2]
# Example 3:
# Input: nums = [3,3], target = 6
# Output: [0,1]
class Solution:
def twoSum(self, nums: list[int], target: int) -> list[int]:
hashmap = {}
for i, num in enumerate(nums):
complement = target - num
if complement in hashmap:
return [hashmap[complement], i]
hashmap[num] = i
return []
def main():
solution = Solution()
nums = [-3,4,3,90]
target = 0
result = solution.twoSum(nums, target)
print(f"The indices that add up to the target are: {result}")
if __name__ == "__main__":
main()